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Find the value of a for which points (a,2a+1) does not lie outside the parabola y=x^2+x+1)
Dear Avni If a point lies inside the curve S,ThenS1 should be less than 0S1 Now2a +1 - a² -a -1 a² -a>0a(a-1) >0Hencea bongs to [1, infinity) and ( - infinity, 0] RegardsArun (askIITians forum expert)
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