Find the value of a for which points (a,2a+1) does not lie outside the parabola y=x^2+x+1)

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Arun · Answer

Dear Avni If a point lies inside the curve S, Then S 1 should be less than 0 S 1 Now 2a +1 - a² -a -1 a² -a>0 a(a-1) >0 Hence a bongs to [1, infinity) and ( - infinity, 0] Regards Arun (askIITians forum expert)

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Find the value of a for which points (a,2a+1) does not lie outside the parabola y=x^2+x+1)

Find the value of a for which points (a,2a+1) does not lie outside the parabola y=x^2+x+1)

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