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```
find the sum of integers between 100 and 200 that are divisible by 100 ​

```
3 months ago

Rituraj Tiwari
1789 Points
```							108,117,126.... 198 and so onSo a=108l=198n= ?nth term= a + (n-1)d198= 108+(n-1)9198= 108+9n-9198-99= 9n99/9= nn= 11Now, sum of n termsSum of first 11 terms= 11/2(108+198)=11/2(306)=11×153=1683
```
3 months ago
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### Course Features

• 53 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions