find the equation of the tangent to the parabola y^2-6x+8y-6=0 which is inclined at an angle of 45 degree to the x axis. Please answer as soon as possible.

Question

Susmita · Answer

y 2 -6x+8y-6=0 derivate wrt x. 2ydy/dx-6+8dy/dx=0 Or,(2y+8)dy/dx=6 Or,dy/dx=6/(2y+8) Also dy/dx=tan45=1 given So 2y+8=1 Or,y=-7/2=-3.5 putting this value of y in equation of curve x=5.7 (you can also express it in p/q form.i am writing in decimal form as it helps typing). so equation of tangent is y=mx+c=x+c and it passes through 5.7,-3.5. So c=-9.2 y=x-9.2

Susmita · Answer

Oops!that would be 2y+8=6. Or,y=1 So x=0.5 Please correct it.and follow the steps.thank you. .........................................................................

Deepak Kumar Shringi · Answer

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find the equation of the tangent to the parabola y^2-6x+8y-6=0 which is inclined at an angle of 45 degree to the x axis. Please answer as soon as possible.

find the equation of the tangent to the parabola y^2-6x+8y-6=0 which is inclined at an angle of 45 degree to the x axis. Please answer as soon as possible.

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