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find the equation of the tangent to the parabola y^2-6x+8y-6=0 which is inclined at an angle of 45 degree to the x axis. Please answer as soon as possible.
y2-6x+8y-6=0derivate wrt x.2ydy/dx-6+8dy/dx=0Or,(2y+8)dy/dx=6Or,dy/dx=6/(2y+8)Also dy/dx=tan45=1 givenSo 2y+8=1Or,y=-7/2=-3.5putting this value of y in equation of curvex=5.7 (you can also express it in p/q form.i am writing in decimal form as it helps typing).so equation of tangent isy=mx+c=x+c and it passes through 5.7,-3.5.So c=-9.2y=x-9.2
Oops!that would be2y+8=6.Or,y=1So x=0.5Please correct it.and follow the steps.thank you..........................................................................
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