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Find the equation of the line perpendicular to the line x – 7y + 5 = 0 and having x-intercept 3
Welcome to AskiitiansThe equation of the line is given as x – 7y + 5 = 0.The above equation can be written in the form y = mx+cThus, the above equation is written as:y= (1/7)x + (5/7)From the above equation, we can say that,The slope of a line, m = 5/7The slope of the line perpendicular to the line having a slope of 1/7 ism = -1/(1/7) = -7Hence, the equation of a line with slope -7 and intercept 3 is given as:y = m (x – d)⇒ y= -7(x-3)⇒ y=-7x + 217x+ y = 21Hence, the equation of a line which is perpendicular to the line x – 7y + 5 = 0 with x-intercept 3 is 7x+ y = 21.Thanks
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