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Find the equation of tangent to the parabola y^2=x at (1, -1)

Find the equation of tangent to the parabola y^2=x at (1, -1)

Grade:12th pass

2 Answers

Deepak Kumar Shringi
askIITians Faculty 4405 Points
3 years ago
2ydy=dx
slope of tangent = -1/2 so equation will be
y+1=-1/2(x-1)
2y+2=-x+1
x+2y+1=0
Saurabh Koranglekar
askIITians Faculty 10341 Points
3 years ago
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