Find the equation of tangent to the parabola y^2=x at (1, -1)

Question

Deepak Kumar Shringi · Answer

2ydy=dx slope of tangent = -1/2 so equation will be y+1=-1/2(x-1) 2y+2=-x+1 x+2y+1=0

Saurabh Koranglekar · Answer

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Find the equation of tangent to the parabola y^2=x at (1, -1)

Find the equation of tangent to the parabola y^2=x at (1, -1)

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Find the equation of tangent to the parabola y^2=x at (1, -1)

Find the equation of tangent to the parabola y^2=x at (1, -1)

2 Answers

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