Find the equation of circle passing through (3, -6) and touching both the axes ?

(a) x² + y² – 6x + 6y +9 =0

(b) x² + y² + 6x – 6y +9 =0

(c) x² + y² – 30x + 30y + 225 =0

(d) x² + y² + 30x – 30y + 225 =0

solution:
ans: “a” and “ c” both

AS given circle is touching both the axis and passing through (3, -6) so its clear that circle would be in 4^thquadrant .. so the center also would be in 4^thquadrant .
so option “a” and “ c” could be the answer..
then we see than .. both “ a” and “c ” is satifing the point (3, -6) so both will the answer.. like given in the image..


thanks and regards