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`        find the area of trapezium when parallel sides are 20 m & 30 m and non parallel sides are 6 m & 8m`
one year ago

Saurabh Koranglekar
8383 Points
```							Let h is the height of trapeziumso,6^2=h^2+x^28^2=h^2+(10-x)^264-36=(10-x)^2- x^228=(10-x-x) 102.8=10-2x7.2 = 2xx=3.6 mand 10-3.6 =6.4 mnow,h={6^2-(3.6)^2}^1/2=4.8 mnow,area of trapezium=1/2 (20+30) x 4.8=2.4 x 50=120 m^2
```
one year ago
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### Course Features

• 53 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions