equation of circle with centre (-1,2) and passing through the centroid of triangle formed by (3,1), (2,-1), and (1,3) is

Dear Student

Coordinates of centroid =( ( x1+x2+x3)/3 , (y1+y2+y3)/3 )
G= ( (6/2) , (3/3) )
G = (2,1)
Now we got centre and a point on circle circumference as well
radius of circle = distance between centre and any point on circumference
by using distance formula
r = √10
Now we got centre,radius.
so equation of circle will be
(x+1)² + (y-2)² = 10

Thanks