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All the possible seven digit numbers are formed by using the digits 1, 2, ........., 7 without repetition. These numbers are then arranged in ascending order. What will be the 2888th number in the given order?

Ronit Dutta , 7 Years ago
Grade 12th pass
anser 1 Answers
Arun

Last Activity: 7 Years ago

Total Possible seven digits numbers = 7! = 5040
Each of these 7 digits will be the starting digits for 5040/7 = 720 nos
 
So 1, 2, 3, 4 will be the starting digits for first 2880 numbers when the numbers are arranged in ascending order. Hence for 2880th term,
We have to check for another 8 terms as-
5123467
5123476
5123647
5123674
5123746
5123764
5124367
5124376
 
Hence 2888th term = 5124376
 
Regards
Arun (askIITians forum expert)

 

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