sir pls solve ths quotion

if a circle of constant radius 3k passes through the origin and meets the axes at A and B the locus of the centeroid of the triangle ABC is.

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Dear rohan

 

 

let centroid of circle is (l,m)

then point A and B will be as shown in figure

and center of circle will be (3l/2 ,3m/2)

 

so  (3k)² =(3l/2)² +(3m/2)²

   (2k)² =(l)² +(m)²

so locus

x² +y² =4k²

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