sir pls solve ths quotionif a circle of constant radius 3k passes through the origin and meets the axes at A and B the locus of the centeroid of the triangle ABC is.

Dear rohan

 

 

let centroid of circle is (l,m)

then point A and B will be as shown in figure

and center of circle will be (3l/2 ,3m/2)

 

so  (3k)² =(3l/2)² +(3m/2)²

   (2k)² =(l)² +(m)²

so locus

x² +y² =4k²

---

Please feel free to post as many doubts on our discussion forum as you can.
 If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly.
 We are all IITians and here to help you in your IIT JEE  & AIEEE preparation.

 All the best.
 
Regards,
Askiitians Experts
Badiuddin