p.t the polar w.r.t the circle x^2+y^2=c^2 of any point on the circle (x+a)^2+(y-b)^2=k^2 always touches the circle (ax+by+c)^2=k^2(x^2+y^2)

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Badiuddin askIITians.ismu Expert · Answer

Dear akash (ax+by+c)^2=k^2(x^2+y^2) does not represent the equation of circle.please check and post again Regards Badiuddin

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p.t the polar w.r.t the circle x^2+y^2=c^2 of any point on the circle (x+a)^2+(y-b)^2=k^2 always touches the circle (ax+by+c)^2=k^2(x^2+y^2)

p.t the polar w.r.t the circle x^2+y^2=c^2 of any point on the circle (x+a)^2+(y-b)^2=k^2 always touches the circle (ax+by+c)^2=k^2(x^2+y^2)

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p.t the polar w.r.t the circle x^2+y^2=c^2 of any point on the circle (x+a)^2+(y-b)^2=k^2 always touches the circle (ax+by+c)^2=k^2(x^2+y^2)

p.t the polar w.r.t the circle x^2+y^2=c^2 of any point on the circle (x+a)^2+(y-b)^2=k^2 always touches the circle (ax+by+c)^2=k^2(x^2+y^2)

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