Vikas TU
Last Activity: 11 Years ago
Let the eqn. of the variable line be y = mx +c
1) distance from point (2,0) is given by:
a1 = mod[(2m + c)/underroot(m^2 + 1)]
2) distance from point (0,2) is given by:
a2 = mod[(-2 + c)/underroot(m^2 + 1)]
3) distance from point (-2,-2) is given by:
a3 = mod[(-2m + 2 +c)/underroot(m^2 + 1)]
Now, a1 + a2 + a3 = 0
=> mod[(2m + c)/underroot(m^2 + 1)] + mod[(-2 + c)/underroot(m^2 + 1)] + mod[(-2m + 2 +c)/underroot(m^2 + 1)] = 0
=> 2m + c -2 +c - 2m + 2 +c = 0
=> 3c = 0
=> c = 0
Therefore, it proves that the line has its intercepts 0 .i.e the line is passing through the fixed point Origin <--------------> (0,0)
plz approve!
plz approve!
plz approve!