Flag Analytical Geometry> parabola...
question mark

The locus of the pole of the chords of the parabola y^2-4ax=0 which subtend right angle at it's vertex is ??

ravi sharma , 11 Years ago
Grade
anser 3 Answers
Likith Narayan ss

Last Activity: 11 Years ago

ler the pole be (x1,y1)  then polar is yy1-2a(x+x1) on homogenising with parabola we get  homogenous pair of straight lines ie           8a2-4ay1xy+2ax1y2=0 since it subtend right angle at vertex then coefficient of x2+ coefficient of y2 =0 therefore 8a2+2ax1 =0 therefore locus is x1+4a=0 , x+4a=0

vivek kumar

Last Activity: 11 Years ago

let the pole be (x1,y1) then polar is yy1-2a(x+x1) on homogenising with parabola we get homogenous pair of straight lines ie 8a2-4ay1xy+2ax1y2=0 since it subtend right angle at vertex then coefficient of x2+ coefficient of y2 =0 therefore 8a2+2ax1 =0 therefore locus is x1+4a=0 , x+4a=0

FITJEE

Last Activity: 11 Years ago

ler the pole be (x1,y1)  then polar is yy1-2a(x+x1) on homogenising with parabola we get  homogenous pair of straight lines ie           8a2-4ay1xy+2ax1y2=0 since it subtend right angle at vertex then coefficient of x2+ coefficient of y2 =0 therefore 8a2+2ax1 =0 therefore locus is x1+4a=0 , x+4a=0

 

 

Provide a better Answer & Earn Cool Goodies

Enter text here...
star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments


Ask a Doubt

Get your questions answered by the expert for free

Enter text here...