Pratham Ashish
Last Activity: 15 Years ago
hi,
in the first coordinate sys,
x/a + y/b = 1 ..............................1
in other
x'/ p + y'/q =1
where
so, x { cos θ/p - sinθ /q } + y { sinθ /p + cosθ/ q } =1
comparing with (1).....
{ cos θ/p - sinθ /q }/ 1/a = { sinθ /p + cosθ/ q } / 1/b = 1/1
cos θ/p - sinθ /q = 1/a ...............2
sinθ /p + cosθ/ q = 1/b ........................3
sq. and adding 2 &3
1/p^2 + 1/q^2 = 1/a^2 + 1/b^2