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question mark

Line 'L' has interceps a and b on the coordinate axis. When the axis are rotated through a given angle, keeping the origin fixed, the same line 'L' has intercepts p and q on the new axis, then

A) a2 + b2 = p2 + q2

B) a2 + p2 = b2 + q2

C) 1/a2 + 1/b2 = 1/p2 + 1/q2

D) 1/a2 + 1/p2 = 1/b2 + 1/q2

raman malik , 16 Years ago
Grade 12
anser 4 Answers
Pratham Ashish

hi,

 in the first coordinate sys,

x/a + y/b = 1     ..............................1

in other

x'/ p + y'/q  =1

where

 

\begin{align} x'&=x\cos\theta+y\sin\theta\\ y'&=-x\sin\theta+y\cos\theta. \end{align}

 

so,  x {  cos θ/p - sinθ /q }   + y { sinθ /p  + cosθ/ q }  =1 

comparing with (1).....

 {  cos θ/p - sinθ /q }/ 1/a   = { sinθ /p  + cosθ/ q }  / 1/b = 1/1

 cos θ/p - sinθ /q   = 1/a  ...............2

sinθ /p  + cosθ/ q  = 1/b ........................3

sq. and adding 2 &3

1/p^2 +  1/q^2  = 1/a^2 + 1/b^2

 

 

 

 

 

 

 

Last Activity: 16 Years ago
Aditya Lather
H
Last Activity: 7 Years ago
Aditya Lather
Here the length of perpendicular from origin to the lines would be equal hence on equating that distance we get
√(1/p^2 +1/q^2)=√(1/a^2+1/b^2)
On squaring both sides we get the answer
Last Activity: 7 Years ago
Kushagra Madhukar
Dear student,
Please find the answer to your question.
 
Here the length of perpendicular from origin to the lines would be equal hence on equating that distance we get
√(1/p^2 +1/q^2)=√(1/a^2+1/b^2)
On squaring both sides we get the answer
Hence the correct option will be C
 
Thanks and regards,
Kushagra
Last Activity: 5 Years ago
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