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Grade 12Analytical Geometry

Line 'L' has interceps a and b on the coordinate axis. When the axis are rotated through a given angle, keeping the origin fixed, the same line 'L' has intercepts p and q on the new axis, then

A) a2 + b2 = p2 + q2

B) a2 + p2 = b2 + q2

C) 1/a2 + 1/b2 = 1/p2 + 1/q2

D) 1/a2 + 1/p2 = 1/b2 + 1/q2

Profile image of raman malik
16 Years agoGrade 12
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4 Answers

Profile image of Pratham  Ashish
16 Years ago

hi,

 in the first coordinate sys,

x/a + y/b = 1     ..............................1

in other

x'/ p + y'/q  =1

where

 

\begin{align} x'&=x\cos\theta+y\sin\theta\\ y'&=-x\sin\theta+y\cos\theta. \end{align}

 

so,  x {  cos θ/p - sinθ /q }   + y { sinθ /p  + cosθ/ q }  =1 

comparing with (1).....

 {  cos θ/p - sinθ /q }/ 1/a   = { sinθ /p  + cosθ/ q }  / 1/b = 1/1

 cos θ/p - sinθ /q   = 1/a  ...............2

sinθ /p  + cosθ/ q  = 1/b ........................3

sq. and adding 2 &3

1/p^2 +  1/q^2  = 1/a^2 + 1/b^2

 

 

 

 

 

 

 

Profile image of Aditya Lather
7 Years ago
H
Profile image of Aditya Lather
7 Years ago
Here the length of perpendicular from origin to the lines would be equal hence on equating that distance we get
√(1/p^2 +1/q^2)=√(1/a^2+1/b^2)
On squaring both sides we get the answer
Profile image of Kushagra Madhukar
5 Years ago
Dear student,
Please find the answer to your question.
 
Here the length of perpendicular from origin to the lines would be equal hence on equating that distance we get
√(1/p^2 +1/q^2)=√(1/a^2+1/b^2)
On squaring both sides we get the answer
Hence the correct option will be C
 
Thanks and regards,
Kushagra