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find the length of the laus rectum of the parabola-
4y^2+2x-20y+17=0
plz help..thanx in advance!!
the above equation can be written as
( 2y-5)^2=2(x+4)
therefore the length of the latus rectum is 2
A small mistake in the above post.
(2y-5)2 = -2x-17+25 = -2x+8 = -2(x-4)
or, (y- 5/2)2 = -1/2 * (x-4)
So Latus Rectum is 1/2 .
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