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Can you tell me how to get combined equation from two lines passing through the same point?
L1 : equation of line 1 : ax +by +c=0
L2 : equation of line 2 : px +qy +r=0
Required equation (L3):L1 + (lambda)*L2 where lambda is a constant
Lets say lambda = H(constant) dont know how to make lambda .
Then the eqution is : (a+ H*p)x+(b+H*q)y+(c+H*r)=0
to get the value of H(lambda) the point given satisfies all the 3 equations L1,L2 and L3 ,put the point in L3 to get value of lambda
Hope this helps
sorry it was my first reply to an answer so made a bit of mistake
the correct equation is L3:- L1+(lambda)*L2=0
this is the general equation of a line passing through the point of intersecti
Different values of lambda give different lines
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