Last Activity: 13 Years ago
2x + y - 4 = 0
y = 4-2x
general point on this line is
P = (x,4-2x)
distance of this point P from line 3x+4y-1 = 0 is 2 units so
3x+4y-1/5 = 2
3x + 4(4-2x) - 1 = 10
x = 1
so general point P = (x,4-2x) = (1,2)
this is the required point
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Last Activity: 2 Year ago(s)