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Find the coordinates of a point on the line 2x+y-4=0 whose distance from 3x+4y-1=0 is 2 units. PLEASE REPLY SOON. Thanks.
2x + y - 4 = 0 y = 4-2x general point on this line is P = (x,4-2x) distance of this point P from line 3x+4y-1 = 0 is 2 units so 3x+4y-1/5 = 2 3x + 4(4-2x) - 1 = 10 x = 1 so general point P = (x,4-2x) = (1,2) this is the required point approve if u like my ans
2x + y - 4 = 0
y = 4-2x
general point on this line is
P = (x,4-2x)
distance of this point P from line 3x+4y-1 = 0 is 2 units so
3x+4y-1/5 = 2
3x + 4(4-2x) - 1 = 10
x = 1
so general point P = (x,4-2x) = (1,2)
this is the required point
approve if u like my ans
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