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Find the equation of the chord of the parabola y 2 = 12x which is bisected at the point (5, –7)

```
9 years ago

```							Dear student,
let (x1,y1) and (x2,y2) be two point be on parabola and (5,-7) is their midpoint
=> x1+x2 = 10 , y1+y2 = -14
yi^2 = 12xi
=> y1^2 + y2^2 = 120 and y1+y2 = -14
=> y1+y2)^2 = 196
=> 120 + 2y1y2 = 196
=> y1y2 = 38 => y2 = 38/y1
substitute it in y1+y2 = -14
=> y1^2 + 14y1 + 38 = 0
=> y1 = -3.68 , x1 = 1.13 and y2 = 10.316 , x2 = 8.869
line passing through (x1,y1) and (x2,y2) is y= (-6/7)x + (-19/7)
```
9 years ago
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