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sir focus is (1,2) and equation of directrix is 3x-4y-15=0 what will be the equation of parabola.sir i have just started parabola so i have small doubts
dear vishal eccentricity of parabola is 1 ... PS = ePM (for any curve) distance of directrix from any point on parabola = (distance bw any point on parabola to focus) (3x-4y-15/5) = {(x-1)2+(y-2)2}1/2 this is the desired eq of parabola .... approve if u like my ans
dear vishal
eccentricity of parabola is 1 ...
PS = ePM (for any curve)
distance of directrix from any point on parabola = (distance bw any point on parabola to focus)
(3x-4y-15/5) = {(x-1)2+(y-2)2}1/2
this is the desired eq of parabola ....
approve if u like my ans
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