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z1,z2,z3 are the vertices of a triangle and are roots of equation z^3-3az^2+3bz+x=0 then the condition for the triangle to be equilateral is: A.a^2=b B.a=b^2 C.a^2=3b D.a=3b^2

z1,z2,z3 are the vertices of a triangle and are roots of equation z^3-3az^2+3bz+x=0 then the condition for the triangle to be equilateral is:
A.a^2=b
B.a=b^2
C.a^2=3b
D.a=3b^2
 

Grade:10

1 Answers

Asim
17 Points
5 years ago
opt A makes it perfect cube  ; if x is 1                                                          it makes it (z-1)^3 = 0      therefore z1 = z2 = z3 = 1  hence an equilateral triangle

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