MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 12

                        

z + ( root 2) | z +1| +i=0 z is a complex number then z is equal to

9 months ago

Answers : (3)

Aditya Gupta
2056 Points
							
let z= x+iy
so x+iy + i + (root 2) | z +1|= 0
x + (root 2) | z +1| + i(y+1)= 0
equating real and imaginary parts to 0,
y+1 = 0 and x + (root 2) | z +1| = 0
so y= – 1
and – x= (root 2) | z +1|= (root 2) | x+1 + iy|
x^2= 2[(x+1)^2 + y^2]= 2[(x+1)^2 + 1]= 2(x^2+2x+2)
or x^2= 2x^2+4x+4
(x+2)^2= 0
x= – 2
so, z= – 2 – i
kindly approve :))
9 months ago
Vikas TU
12141 Points
							
Dear student 
Please check out the study materials for more such examples
Good Luck 
9 months ago
Srutarshi Tripathi
38 Points
							
Since , z + \/2 I z+1 I + i = 0
the middle term is purely real. So, Im(z+i)=0 or Im(z) + 1 =0 
or, Im(z) = -1
Now, let z= x – i
Hence , the equation reduces to :
x + \/(2( (x+1)2 + 1) ) =0
or, x= 2(x+1)2 + 2
or, x2 = 2x2 + 4x + 4
or, x2 + 4x + 4 =0
or, x = – 2
So, z = – 2 – i (ANSWER)
6 days ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details