Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        z + (root 2) | z +1|+i=0z is a complex number then z is equal to  `
2 months ago

## Answers : (2)

1819 Points
```							let z= x+iyso x+iy + i + (root 2) | z +1|= 0x + (root 2) | z +1| + i(y+1)= 0equating real and imaginary parts to 0,y+1 = 0 and x + (root 2) | z +1| = 0so y= – 1and – x= (root 2) | z +1|= (root 2) | x+1 + iy|x^2= 2[(x+1)^2 + y^2]= 2[(x+1)^2 + 1]= 2(x^2+2x+2)or x^2= 2x^2+4x+4(x+2)^2= 0x= – 2so, z= – 2 – ikindly approve :))
```
2 months ago
Vikas TU
10081 Points
```							Dear student Please check out the study materials for more such exampleshttps://www.askiitians.com/iit-jee-algebra/complex-numbers/Good Luck
```
2 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

## Other Related Questions on Algebra

View all Questions »

### Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 101 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions