|z – i| is less than pr equal to 2 and z2 = 5+3i , then the maximum value of |iz+ z2| is a) 2+sqrt(31) b)7 c) sqrt(31) – 2 d)none of these

Question

|z – i| is less than pr equal to 2 and z2 = 5+3i , then the maximum value of |iz+ z2| is a) 2+sqrt(31) b)7 ​c) sqrt(31) – 2 d)none of these

Saurabh Koranglekar · Answer

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|z – i| is less than pr equal to 2 and z2 = 5+3i , then the maximum value of |iz+ z2| is a) 2+sqrt(31) b)7 c) sqrt(31) – 2 d)none of these

|z – i| is less than pr equal to 2 and z2 = 5+3i , then the maximum value of |iz+ z2| is
a) 2+sqrt(31)
b)7
c) sqrt(31) – 2
d)none of these

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|z – i| is less than pr equal to 2 and z2 = 5+3i , then the maximum value of |iz+ z2| is a) 2+sqrt(31) b)7 ​c) sqrt(31) – 2 d)none of these

|z – i| is less than pr equal to 2 and z2 = 5+3i , then the maximum value of |iz+ z2| is a) 2+sqrt(31)b)7​c) sqrt(31) – 2d)none of these

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|z – i| is less than pr equal to 2 and z2 = 5+3i , then the maximum value of |iz+ z2| is a) 2+sqrt(31) b)7 c) sqrt(31) – 2 d)none of these

|z – i| is less than pr equal to 2 and z2 = 5+3i , then the maximum value of |iz+ z2| is
a) 2+sqrt(31)
b)7
c) sqrt(31) – 2
d)none of these