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|z – i| is less than or equal to 2 and z2 = 5+3i , then the maximum value of |iz+ z2| is a) 2+sqrt(31) b)7 ​c) sqrt(31) – 2 d)none of these
|z – i| is less than or equal to 2 and z2 = 5+3i , then the maximum value of |iz+ z2| is a) 2+sqrt(31)b)7​c) sqrt(31) – 2d)none of these


2 years ago

Arun
25768 Points
							Dear Meghendra $\hspace{-18}Given |z-i|\leq 2 and z' = 5+3i\;, Then we calculate \max|iz+z'|\\\\\ So |iz+z'| = |i(z-i)+4+3i|\leq |i(z-i)|+|4+3i|\leq |i||z-i|+5\\\\So we get |iz+z'|\leq |z-i|+5=2+5=7\\\\So we get \max|iz+z'| = 7$  Hope it helps In case iof any query please feel free to ask. RegardsArun (askIITians forum expert)

2 years ago
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