Grade 12Algebra
|z-1|=Max(|z-2|,|z|)Then Re(z)=? Answer is 1/2.Please explain?
1 Answer
Vikas TU
Dear Student,
z = x+iy
z-2 = (x-2) + iy
│z │= x2 + y2
│z-2│= (x-2)2 + y2
Max(|z-2|,|z|) = x2 + y2 when Re(z)=1
= x2 + y2 when Re(z)>1
= (x-2)2 + y2 when Re(z)
|z-1|=Max(|z-2|,|z|)
(x-1)2 + y2 = x2 + y2
x = ½
Re(z) = ½
Cheers!!
Regards,
Vikas (B. Tech. 4th year
Thapar University)
Thapar University)
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