Join now for JEE/NEET and also prepare for Boards Join now for JEE/NEET and also prepare for Boards. Register Now
Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
ydx + x[logy/x]dy - 2xdy=0 solve using variable separable method? ydx + x[logy/x]dy - 2xdy=0 solve using variable separable method?
ydx + x[logy/x]dy - 2xdy=0ydx -xdy +x[logy/x]dy -xdy = 0divide by x^2(ydx-xdy)/x^2 + (logy/x - 1)/x^2 . dy = 0-d(y/x) +(logy/x-1)(y/x)^2 / y^2 .dy = 0Take y/x=zdz - (logz-1)z^2/y^2 dy = 0dz(z^2)(logz-1) = dy/y^2Now integrate it as the variables are separated and put z = y/x at the end.Thanksbharat BajajIIT Delhiaskiitians faculty
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -