0

Guest

Courses New

y=mx is a chord of the circle of radius `a` through the origin & whose diameter is along the axis of x. Find the equation of the circles whose diameter is the chord. Hence find the locus of its center for all values of m.

y=mx is a chord of the circle of radius `a` through the origin & whose diameter is along the axis of x. Find the equation of the circles whose diameter is the chord. Hence find the locus of its center for all values of m.

Grade:12th pass

1 Answers

Sunil Raikwar
askIITians Faculty 45 Points
8 years ago
Since circle passes through the origin & diameter along the x-axis therefore its centre is (a,0) and its eq. is (x-a)2+y2=a2or x2+y2-2ax=0.............1
equation of the circle passing through the circle(1) & y=mx
x2+y2-2ax+c(y-mx)=0 where c is any constant its center is(a+m/2,-c/2)
center lies on y=mx
-c/2=m(a+m/2)
putting the value of c in eq be get the required answer.

Thanks & Regards
Sunil Raikwar
askIITian's Faculty



Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

Other Related Questions on Algebra

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More