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Grade: 12th pass
        y=mx is a chord of the circle of radius `a` through the origin & whose diameter is along the axis of x. Find the equation of the circles whose diameter is the chord. Hence find the locus of its center for all values of m.
6 years ago

Answers : (1)

Sunil Raikwar
askIITians Faculty
45 Points
							Since circle passes through the origin & diameter along the x-axis therefore its centre is (a,0) and its eq. is (x-a)2+y2=a2or x2+y2-2ax=0.............1
equation of the circle passing through the circle(1) & y=mx
x2+y2-2ax+c(y-mx)=0 where c is any constant its center is(a+m/2,-c/2)
center lies on y=mx
-c/2=m(a+m/2)
putting the value of c in eq be get the required answer.

Thanks & Regards
Sunil Raikwar
askIITian's Faculty



6 years ago
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