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{(x n ) (n-1)/n } 1/(n+1) is equal to (a) x n (b) x n+1 (c) x n-1
Solving this to one extent, {(xn)(n-1)/n}1/(n+1) = > (x)(n-1)/(n+1) as n cannot be equal to zero that is out of its domain put n = 1 and cross check the options,Therefore,at n = 1x^0 = 1check putting n = 1 in options that gives 1 as the result.That is last option ©.
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