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(x+iy)3=a+ib then prove that x/a+y/b=4(a2-b2) how can i prove this question

DIMPAL BORUAH , 6 Years ago
Grade 11
anser 1 Answers
Arun

Last Activity: 6 Years ago

Dear student
 
(x + iy) = [ a ^3 + (ib)^3 + 3abi (a + ib) ] 
= a^3 - ib^3 + 3a^2bi - 3ab^2 
= (a^3 - 3ab^2) + i (3a^2b - b^3 ) 
=> (x + iy) = a (a^2 - 3b^2 ) + ib (3a^2 - b^2 ) 

comparing the value of x and y both sides 
x = a(a^2 - 3b^2) , y = b (3a^2 - b^2) 

therefore (x/a) = (a^2 - 3b^2) and (y/b) = (3a^2 - b^2) 
(x/a) + (y/b) = 4a^2 - 4b^2 = 4 (a^2 - b^2) 
hence proved
 
 
 
Regards
Arun (askIITians forum expert)

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