Grade upto college level Algebra
x*e^-x +1=0. find no.of roots in {-1,-1/2}
1 Answer
Sher Mohammad
f(x)=x*e^(-x)+1 e=2.73
f(-1)=-e+1 <0
f(-1/2)=1/2e^(-1/2)+1 >0
f(x) monotonic function , imply there exitst a one root of function.
sher mohammad
b.tech, iit delhi
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