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Grade: upto college level

                        

x*e^-x +1=0. find no.of roots in {-1,-1/2}

6 years ago

Answers : (1)

Sher Mohammad
IIT Delhi
askIITians Faculty
174 Points
							f(x)=x*e^(-x)+1  e=2.73
f(-1)=-e+1 <0
f(-1/2)=1/2e^(-1/2)+1 >0

f(x) monotonic function , imply there exitst a one root of function.

sher mohammad
b.tech, iit delhi
6 years ago
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