x*e^-x +1=0. find no.of roots in {-1,-1/2}

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Sher Mohammad · Answer

f(x)=x*e^(-x)+1 e=2.73 f(-1)=-e+1 <0 f(-1/2)=1/2e^(-1/2)+1 >0 f(x) monotonic function , imply there exitst a one root of function. sher mohammad b.tech, iit delhi

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x*e^-x +1=0. find no.of roots in {-1,-1/2}

x*e^-x +1=0. find no.of roots in {-1,-1/2}

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x*e^-x +1=0. find no.of roots in {-1,-1/2}

x*e^-x +1=0. find no.of roots in {-1,-1/2}

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