Grade 12th passAlgebrax*e^-x +1=0. find no.of roots in {-1,-1/2} John Doe 12 Years agoGrade 12th pass
Arun KumarApproved Tutor Answer12 Years ago Hello Student, f(x)=x*e^(-x)+1=>f(-1)=-e+1 <0=>f(-1/2)=1/2e^(-1/2)+1 >0 because f(x) is monotonic=>only one root Thanks & RegardsArun KumarBtech, IIT DelhiAskiitians Faculty