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x and y are real numbers and x>y x^2-xy+y^2=15 xy+x+y=13 find x^2+6y
x^2-xy+y^2+3(xy+x+y)=15+3*13=64(x+y)^2+3(x+y)=64let x+y=zz^2+3z-64=0x+y, 6.63, -.9.63xy=13-6.63=.37use the above two equation to calculate x^2+6y
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