Last Activity: 7 Years ago
Let x^3/2=y than equation becomes y + 1/y=1 or y^2 + 1 = y since x^3/2=y therefore x^3=2y so we get x^3.x^3.x^3=8y^3 or x^3.x^3.x^3=8(y^2+1)^3 (since y=y^2+1)As y^2+1 is always positive so its minimum value will be on y=0 that is 1so x^3.x^3.x^3= 8(0^2+1)^3= 8
Prepraring for the competition made easy just by live online class.
Full Live Access
Study Material
Live Doubts Solving
Daily Class Assignments
Get your questions answered by the expert for free
Last Activity: 1 Year ago
Last Activity: 1 Year ago
Last Activity: 2 Years ago