|x-1|-2|x-3|+3|x+1|=10 x=?........................

Question

|x-1|-2|x-3|+3|x+1|=10 x=?.................................. ...................................................................... . .............. X=?

dhirendra · Accepted Answer

x=1 , x=3 and x=–1 are the points where modulus changes its sign.therefore,i] when x we get , 1 – x + 2x – 6 – 3 – 3x = 10x = – 9 (on solving)x = – 9 lies in the above chosen interval thus can be accepted.ii] when –1we get , –x – 1 + 2x – 6 + 3x + 3 = 10x = 7/2 (on solving)x = 7/2 does not lie in the chosen interval thus is rejected.iii] when 1we get , x – 1 + 2x – 6 + 3x + 3 = 10x = 7/3 (on solving)x = 7/3 lies in the chosen interval thus can be accepted.iv] when x>3we get , x – 1 – 2x + 6 + 3x + 3 = 10x = 1 (on solving)x = 1 does not lie in the interval thus rejected. the acceptable values of x are the answer, ie; x = –9 and x = 7/3

Algebra> |x-1|-2|x-3|+3|x+1|=10 x=?..................

|x-1|-2|x-3|+3|x+1|=10 x=?.................................. ...................................................................... . .............. X=?

Balmukund , 8 Years ago

dhirendra

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Algebra> |x-1|-2|x-3|+3|x+1|=10 x=?..................

|x-1|-2|x-3|+3|x+1|=10 x=?.................................. ...................................................................... . .............. X=?

Balmukund , 8 Years ago

dhirendra

LIVE ONLINE CLASSES

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