0

Guest

Courses New

what is the value of constant C in the Langrange mean value theorem,if f(x)=2x^2+3x+4 in [1,2]?

what is the value of constant C in the Langrange mean value theorem,if f(x)=2x^2+3x+4 in [1,2]?

Grade:Upto college level

1 Answers

Jitender Singh IIT Delhi
askIITians Faculty 158 Points
9 years ago
Ans:
f'(c) = \frac{f(b)-f(a)}{b-a}
f'(c) = \frac{f(2)-f(1)}{2-1}
f'(c) = \frac{18-9}{2-1} = 9
f(x) = 2x^{2}+3x+4
f'(x) = 4x+3 = 9
\Rightarrow x = \frac{3}{2}
\Rightarrow c = \frac{3}{2}
Thanks & Regards
Jitender Singh
IIT Delhi
askIITians Faculty

Think You Can Provide A Better Answer ?

Other Related Questions on Algebra

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More