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        what is the value:(cos pi/2+isinpi/2)(cospi/2 square+isinpi/2 suqare)(cospi/2 cube+isinpi/2cube)...upto infinity
2 years ago

Arun
23543 Points
							Dear Tarun When you put the de moivre theorem,You getcos($\pi$/2 + $\pi$/2² + $\pi$/2³+.....) + i sin ($\pi$/2 + $\pi$/2² + $\pi$/2³+.....) Since bracket is a sum of infinite terms of G.P.HenceSum = ($\pi$/2)/(1- 1/2) = $\pi$NowThe expression becomes asCos  $\pi$ + i sin $\pi$= -1 + 0= -1 RegardsArun (askIITians forum expert)

2 years ago
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• 101 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions