what is the area of parallelogram formed by the tangents at points having eccentric angle as theta,theta + pie/2, pie + theta, 3pie/2 + theta for an ellipse of the standard form x^2/a^2 + y^2/b^2 =1 ??

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Rinkoo Gupta · Answer

area of parallelogram=product of axes=(2a)(2b)=4ab Thanks & Regards Rinkoo Gupta AskIITians faculty

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what is the area of parallelogram formed by the tangents at points having eccentric angle as theta,theta + pie/2, pie + theta, 3pie/2 + theta for an ellipse of the standard form x^2/a^2 + y^2/b^2 =1 ??

what is the area of parallelogram formed by the tangents at points having eccentric angle as theta,theta + pie/2, pie + theta, 3pie/2 + theta for an ellipse of the standard form x^2/a^2 + y^2/b^2 =1 ??

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