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what is the area of parallelogram formed by the tangents at points having eccentric angle as theta,theta + pie/2, pie + theta, 3pie/2 + theta for an ellipse of the standard form x^2/a^2 + y^2/b^2 =1 ??

what is the area of parallelogram formed by the tangents at points having eccentric angle as theta,theta + pie/2, pie + theta, 3pie/2 + theta for an ellipse of the standard form x^2/a^2 + y^2/b^2 =1 ??

Grade:12

1 Answers

Rinkoo Gupta
askIITians Faculty 80 Points
8 years ago
area of parallelogram=product of axes=(2a)(2b)=4ab
Thanks & Regards
Rinkoo Gupta
AskIITians faculty

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