Falling Behind in Studies? Join Our Performance Improvement Batch. Enroll For Free
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Live 1-1 coding classes to unleash the creator in your Child
what are the solutions of following equation? Ix 3 -6x 2 +11x-6I
Through trial an error method we can see that (x-1) is a factor. Then by vanishing method the polynomial can be solved as :f(x) = x^3-6x^2+11x-6= x^3-x^2-5x^2+5x+6x-6= x^2(x-1) -5x(x-1) +6(x-1)= (x-1)(x^2-5x+6)= (x-1)(x-2)(x-3)So under modulus function it becomes |(x-1)(x-2)(x-3)| Now it f(x) > 0 when x > 3 f(x)
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -