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`        Vdvdall the values of a for which the quadratic expression ax^2 +(a-2)x -2 is negative for exactly two integral values of x lie in which interval.`
6 months ago

1807 Points
```							Â obviouslyÂ aÂ should be positive else it would be negative for infinite values of x.now,Â ax^2 +(a-2)x -2= (x+1)(ax â€“ 2)= a(x+1)(x â€“ 2/a)Â by using wavy curve we can draw its sign scheme and note that it is negative in the interval (1, 2/a)obviously 0 is an integer in this interval and indeed f(0)= â€“ 2 is negative. since there must e exactly 2 such integers, the next integer is 1, so2/a should be greater than 1.butÂ 2/a should be less than 2 else there would be 3 such integers.solving this above 2 inequalities, we geta lies in interval [1, 2).kindly approve :)
```
6 months ago
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• 101 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions