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`        Vdvdall the values of a for which the quadratic expression ax^2 +(a-2)x -2 is negative for exactly two integral values of x lie in which interval.`
one year ago

2043 Points
```							 obviously a should be positive else it would be negative for infinite values of x.now, ax^2 +(a-2)x -2= (x+1)(ax – 2)= a(x+1)(x – 2/a) by using wavy curve we can draw its sign scheme and note that it is negative in the interval (1, 2/a)obviously 0 is an integer in this interval and indeed f(0)= – 2 is negative. since there must e exactly 2 such integers, the next integer is 1, so2/a should be greater than 1.but 2/a should be less than 2 else there would be 3 such integers.solving this above 2 inequalities, we geta lies in interval [1, 2).kindly approve :)
```
one year ago
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• Test paper with Video Solution
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• Discussion Forum
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