Grade 12th passAlgebra

Vase I contains 2 white and 4 black balls and Vase II contains 4 white and 4 black balls. If a ball is drawn out at random from one of the two vases, what is the probability that it is a white ball?

Vishal singh

9 Years agoGrade 12th pass

2 Answers

Vikas TU

9 Years ago

Dear Student,

probability of selecting one vase=1/2

Probability of selecting white ball from vase 1 = 2/6

Probability of selecting white ball from vase 2 = 4/8

Therefore, Probability of selecting white ball at randim from one of the two vases= (1/2)x(2/6) + (1/2)x(4/8)

= 1/6 + ¼

= 5/12

Cheers!!

Regards,

Vikas (B. Tech. 4^th year
Thapar University)

Dheeraj Upadhyay

6 Years ago

The probability of first one will be

no.of white balls / total no. of balls

i.e. 2/6=1/3

the probability of second one will be:

no. of white balls / total no. of balls

i.e. 4/8

=1/2

total probability :

no.of white balls / total no. of balls

i.e. 6/14

=3/7