Flag Algebra> Value of (a–c)[(a–b) 2 +(b–c) 2 –(a–b)(b–...
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Value of (a–c)[(a–b)2 +(b–c)2 –(a–b)(b–c)]+(c–a)3 is equal to(1) 3(a – b) (b – c) (c –a) (2) (a – b) (b – c) (c – a)(3)(a–b)3 (b–c)3 (c–a)3 (4)None of these

Vijay , 7 Years ago
Grade 10
anser 1 Answers
Arun

Last Activity: 7 Years ago

Solution

={(a-b)+(b-c) }{(a - b)^2 + (b - c)^2 - (a - b) (b - c)} + (c - a)^3

(x+y) (x^2 - xy+y^2) =x^3 + y^3

=(a-b)^3 +(b-c)^3 +(a-c) ^3

On solving it further

=0

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