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Under what conditions the function y =(ax+b)/(cx+d), (ad- bc)not= 0 is it’s own inverse?
First inverse the function :x = ay + b / cy + dxcy + dx = ay + by = b - dx/ cx - aIt should be equal to original functionb - dx/ cx - a = ax + b/cx + dbcx + bd - dcx^2 - d^2x = acx^2 + bcx - a^2x - abBy this, we get a = -d should be the other condition.ThanksBharataskiitians facultyIIT Delhi
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