SHAIK AASIF AHAMED
Last Activity: 10 Years ago
let A=(4,-3) B=(-2,5) and orthocentre O=(1,2)
slope of altitude coming from A =

BC slope =3/5(as it is perpendicular to altitude coming from A)
Equation of line through BC is y=(3/5)x+c
substituting (-2,5) in above eqn we get c=31/5
so equation is 5y=3x+31........(1)
similarly altitude coming from B slope=

AC slope =1
Equation of AC is y=x+c
substituting A(4,-3) we get
c=-7
equation is y=x-7.....(2)
solving (1) and (2) we get third vertex as (33,26)
Thanks and Regards
Shaik Aasif
askIITians Faculty