SHAIK AASIF AHAMED
Last Activity: 10 Years ago
Hello student,
There are three cases for first two cards be drawn:
(i) two cards drawn are aces:
Probability in this case = Probability of getting 2 aces * Probability of getting third card to be an ace
(ii) one isace, one is not:
Probability in second case =
(iii) none of them is ace:
Probability in third case =
As, all the three cases are mutually exclusive , therefore by using addition theorem,
Thanks and Regards
Shaik Aasif
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