#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

# total number of seven digits ,, sum of whose digits is even .. (repitition is allowed)

SHAIK AASIF AHAMED
6 years ago
Hello student,
There are 9000000 seven digit numbers exist.
(because
smallest 7 digit number is 1000000 greatest 7 digit number is 9999999
So total number of 7 digit numbers=9999999 - 1000000+1).
Out of 9000000 numbers 4500000 are having the sum of digits as even and the remaining 4500000 are having the sum of digits as odd.
SinceEvery alternate number has its sum of digits even and odd.
For e.g. Sum of digits in 11 is 2 which is even. Sum of digits of 12 is 3 which is odd. Again sum of digits of 13 is even and that of 14 is odd. There are 9000000 seven digit numbers. So half of it is 4500000
So the required answer is 4500000.
10 months ago
Dear student,

There are 9000000 seven digit numbers exist.
Since smallest 7 digit number is 1000000 greatest 7 digit number is 9999999
So total number of 7 digit numbers = 9999999 – 1000000 + 1.
Out of 9000000 numbers 4500000 are having the sum of digits as even and the remaining 4500000 are having the sum of digits as odd.
Since Every alternate number has its sum of digits even and odd.
For e.g. Sum of digits in 11 is 2 which is even. Sum of digits of 12 is 3 which is odd. Again sum of digits of 13 is even and that of 14 is odd. There are 9000000 seven digit numbers. So half of it is 4500000
So the required answer is 4500000.

Hope it helps.
Thanks and regards,
Kushagra