to the circle x^2+y^2+8x-4x+4=0 tangent at the point theta=pie/4 is

Question

Arun · Answer

Dear student Please confirm as I think that you forgot to add y terms. -4x is correct or ot should be – 4y ? Please specify this

Mrunal Sonawane · Answer

yah......................................... it is -4y please give me solution sir.........................................................

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to the circle x^2+y^2+8x-4x+4=0 tangent at the point theta=pie/4 is

to the circle x^2+y^2+8x-4x+4=0 tangent at the point theta=pie/4 is

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to the circle x^2+y^2+8x-4x+4=0 tangent at the point theta=pie/4 is

to the circle x^2+y^2+8x-4x+4=0 tangent at the point theta=pie/4 is

2 Answers

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Other Related Questions on Algebra

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