the square rootCheck this first: and get an idea how to solve:
of √(999x1000x1001x1002+1)
Let y = n2+3n
Then, the given expression is y(y+2)+1 = y2+2y+1 = (y+1)2 = (n2+3n+1)2.
Hence, the square root is n2+3n+1 . Substitue n = 999, and you get the square root as 1000999