Grade 12th passAlgebraTo find the square root of the product 998×999×1000×1001×1002 Sambit Dash 10 Years agoGrade 12th pass
Vikas TU10 Years agoWe have 998n(n+1)(n+2)(n+3) = > 998 (n2+3n)(n2+3n+2)let (n2+3n) = y=> 998y(y+2)=> 998(y^2 + 2y +1 – 1)=> 998[(y+1)^2 -1]=>998[(n2+3n +1)^2 – 1]here substitute n = 999 with root whole.