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Grade: 12th pass
        Three randomly chosen non negative integers x, y and z are found to satisfy the equation x + y + z =10. Then find the probability that z is even.
7 months ago

Answers : (3)

Arun
12364 Points
							
Dear Ayush
 
Total number of solutions  = 10+3 –1 C 3 –1  = 66
favourable number of soutions = 11 C1 + 9 C1 + 7C1 + 5C1 + 3C1 + 1C1 = 36
hence probability (required) = 36/ 66 = 6/11
Regards
Arun (askIITians forum expert)
7 months ago
Yatish
12 Points
							
They have provided that x,y and z are three non negative integers(basically, whole numbers) 
Therefore, either x or y or z will be ==0.
So, z can be equal to 0 or 1 or 2 or 3 or 4 or 5 or 6 or 7 or 8 or 9 or 10.
Among those events, 6 of them are even (,0,2,4,6,8,10)
since 11 is the total possible outcomes.
Probability(z is even)= 6/11
5 months ago
Yatish
12 Points
							
 
[Edited]
They have provided that x,y and z are three non negative integers(basically, whole numbers) 
Therefore, either x or y or z will be >=0 and =
So, z can be equal to 0 or 1 or 2 or 3 or 4 or 5 or 6 or 7 or 8 or 9 or 10.
Among those events, 6 of them are even (0,2,4,6,8,10)
since 11 is the total possible outcomes.
Probability(z is even)= 6/11
5 months ago
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