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three numbers are chosen at random without replacement from {1,2,3,....10}.the probability that the minimum of the chosen numbers in 3 or their maximum is 7 is

Avishkar Jayvant Patil , 8 Years ago
Grade 12
anser 1 Answers
Arun
 
Number of elements in sample space = 10C3 =120 
According to the question 3 & 7 must get chosen and the third no. should be between them (ie 4 or5 or 6)as per condition .
So, no of favourable cases =  3C1 =3
Therefore required probablity = 3/120 = 1/40
Last Activity: 8 Years ago
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