Jayant Kishore
Last Activity: 9 Years ago
Number of elements in sample space = 10C3 =120
According to the question 3 & 7 must get chosen and the third no. should be between them (ie 4 or5 or 6)as per condition .
So, no of favourable cases = 3C1 =3
Therefore required probablity = 3/120 = 1/40
Approve the answer if correct .